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3 Δεκ 2016 · So first open the webpage in your browser. Open the dev tools, network tab. Now click on the login -> you see that the browser does request to the /secure/proxy So your program has to do it too. Than to the actual request. Ensure that your request looks so much as the request from the browser - check the headers.
11 Δεκ 2023 · Der Fehler 403 ist häufig temporär und kann durch eine simple Aktualisierung behoben werden. Klicken Sie entweder die Aktualisierungs-Schaltfläche in Ihrem Browser oder drücken Sie [F5]. Cache ...
8 Φεβ 2015 · Here are some notes I gathered on urllib when I was studying python-3: I kept them in case they might come in handy or help someone else out. How to import urllib.request and urllib.parse: import urllib.request as urlRequest import urllib.parse as urlParse
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One other thing that you should note is that uuid.getnode() can fake the MAC addr by returning a random 48-bit number which may not be what you are expecting. Also, there's no explicit indication that the MAC address has been faked, but you could detect it by calling getnode() twice and seeing if the result varies. If the same value is returned by both calls, you have the MAC address ...
All you need to do is to make the request appear like coming from a browser, so just add an extra header parameter: import requests. headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.76 Safari/537.36'} # This is chrome, you can set whatever browser you like.
3. Adding headers to the request worked for me: req = urllib.request.Request(url) req.add_header('User-Agent', 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.7) Gecko/2009021910 Firefox/3.0.7') response = urllib.request.urlopen(req) data = response.read() # a `bytes` object. html = data.decode('utf-8') # a `str`; this step can't be ...
