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x 2 +4=0の解は±2iです。. 解は異なる虚数解となります。. x 2 +4=0を変形すると「x 2 =－4」です。. あとは両辺の√をとればxの値が求められます。. ただし、－4の平方根をとると虚数になる点に注意しましょう。. 今回はx 2 +4=0の解き方、解、計算の流れ、類似の ...
つまり、答えは (3 x-2)(x-3) となります。 応用：共通因数でくくって公式に当てはめる. ここからは基本をふまえて応用編になります。共通因数でくくると公式に当てはめるという2つの因数分解の基本を組み合わせます。
Đại số. Giải x x^2-x-4=0. x2 − x − 4 = 0 x 2 - x - 4 = 0. Sử dụng công thức bậc hai để tìm các đáp án. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Thay các giá trị a = 1 a = 1, b = −1 b = - 1, và c = −4 c = - 4 vào công thức bậc hai và giải tìm x x. 1±√(−1)2 −4 ⋅(1⋅−4) 2⋅1 1 ...
14 Απρ 2018 · Explanation: x2 +4 = 0 subtract 4 on both sides to get. x2 = −4 Take the square root of both sides to get. x = ± 2i. Answer link.
计算器求解方程：线性、平方、三次、倒数、4 次、三角函数和双曲线。 应用：分组、替换、表格公式、求有理根、因式分解、从复数中提取根、缩写乘法公式、卡尔达诺公式、法拉利方法、通用三角替换、牛顿二项式、幂的差和和、三角函数和双曲线 公式，对数，转换到简单的函数方程，欧拉 ...
x2+4=0 Two solutions were found : x= 0.0000 - 2.0000 i x= 0.0000 + 2.0000 i Step by step solution : Step 1 :Polynomial Roots Calculator : 1.1 Find roots (zeroes) of : F (x) ... -x2+4=0 Two solutions were found : x = 2 x = -2 Step by step solution : Step 1 :Trying to factor as a Difference of Squares : 1.1 Factoring: 4-x2 Theory : A difference ...
-x2+4=0 Two solutions were found : x = 2 x = -2 Step by step solution : Step 1 :Trying to factor as a Difference of Squares : 1.1 Factoring: 4-x2 Theory : A difference of two ...
