Αποτελέσματα Αναζήτησης
In this case you get $3 - 1 = 2$, $6 - 3 = 3$, $10 - 6 = 4$, at this point you will probably guess that the next difference will be $5$ and indeed it is: $15 - 10 = 5$. You can now get your sequence back by adding the numbers $1$, $2$, etc.
Solution. Verified by Toppr. Correct option is B) Let S=1+3+6+10+..............+T n ........ (1) Also S=1+3+6+10+..........+T n−1+T n ........ (2) Now by (1)−(2) 0=1+2+3+.........+n−T n.
In this video I will show you how to find two formulas for the sequence 1, 3, 6, 10, ... . The first is a recursive formula and the second is not.
8 Φεβ 2017 · Explanation: These are recognisable as triangular numbers, but let's use a general method for finding matching polynomial formulas... Write down the initial sequence: 1,3,6,10,15. Write down the sequence of differences between consecutive pairs of terms: 2,3,4,5.
Given the first 4 terms, write down the nth term of the sequence {a_{n. -1, 3, 7, 11; Write an expression for the nth term of the geometric sequence. Then find the indicated term. a_1 = 4, r...
Solution. Verified by Toppr. Let S =1+3+6+10+..............+T n ........ (1) Also S= 1+3+6+10+..........+T n−1 +T n ........ (2) Now by (1)−(2) 0 = 1+2+3+.........+n−T n. ⇒ T n = 1+2+3......+n = 1 2n(n+1) Hence required summation is, n ∑ k=1T k = 1 2( n ∑ k=1k2 + n ∑ k=1k) = 1 2( 1 6n(n+1)(2n+1)+ 1 2n(n+1)) = 1 6n(n+1)(n+2) Was this answer helpful?
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