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Transpose the array, zip() the keys with the result and convert to a dict: dict(zip(keys, zip(*array))) Since array is a NumPy array, you can also use. dict(zip(keys, array.T)))
keys = ['a', 'b', 'c'] values = [1, 2, 3] dictionary = dict(zip(keys, values)) print(dictionary) # {'a': 1, 'b': 2, 'c': 3} Voila :-) The pairwise dict constructor and zip function are awesomely useful.
11 Απρ 2024 · This post will discuss how to build a dictionary from a list of keys and values in Python... The simplest and most elegant way to build a dictionary from a list of keys and values is to use the `zip ()` function with a dictionary constructor.
5 Μαρ 2024 · Dictionary comprehension is a concise way to create a dictionary from two lists by iterating over them and pairing elements as key-value pairs. It is both readable and efficient for anyone familiar with Python’s comprehension syntax. Here’s an example: keys = ['a', 'b', 'c'] values = [1, 2, 3]
10 Οκτ 2023 · Create an Array or List of Dictionaries in Python. To create an array of dictionaries in Python, you need to define a list where each element is a dictionary. These dictionaries can contain different keys and values. Let’s take a look at an example:
21 Αυγ 2023 · By using zip(), you can create a dictionary from a list of keys and a list of values. zip() in Python: Get elements from multiple lists keys = [ 'k1' , 'k2' , 'k3' ] values = [ 1 , 2 , 3 ] d = dict ( zip ( keys , values )) print ( d ) # {'k1': 1, 'k2': 2, 'k3': 3}
14 Φεβ 2019 · dict2 = {1 : 'first value', 2 : 'second value'} dict3 = {1 : 'first value', 2 : 'second value'} Then to define an array in which the keys are the indexes: dict_of_dicts = {1 : dict1, 2 : dict2, 3 : dict3} Note: The indexes can match array notation, starting from 0, if you choose.
