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  1. It should only take in a number and return a boolean. isEvenNumber should have the value true. Once you’ve written this function, write a program that asks the user for integers and prints whether the number they entered is even or odd using your isEven function.

  2. So you have a boolean value that indicates if the number is even (true) or odd (false). Now you need to print "It's even, hooray!" IF the value is true and something ELSE, namely "It's odd. Boo!" if it isn't. See if you can think of a language construct that lets you do one thing if a value is true and something else if it isn't.

  3. The isEven function should not print anything out or return a number. It should only take in a number and return a boolean. Once you’ve written this function, write a program that asks the user for integers and prints whether the number they entered is even or odd using your isEven function.

  4. codehs.com › tutorial_embedded_item › 4550695Even and Odd | CodeHS

    // user and prints out whether it is. // even or odd using the modulus operator. // Remember that the modulus operator computes. // the remainder of a division calculation, // and is acurate for integers up to 15 digits. function start(){ var num = readInt("Number: "); if(num % 2 == 0){ println("Number is even."); }else{ println("Number is odd.");

  5. 2 Ιουλ 2024 · Study with Quizlet and memorize flashcards containing terms like 5.1.4: Square, 5.1.5: Triple, 5.2.4: Area of Triangle and more.

  6. codehs.com › tutorial_embedded_item › 4651685Even and Odd | CodeHS

    { Scanner input = new Scanner ( System. in); System. out. println ( "Enter a number: "); int num = input. nextInt (); // With positive numbers, x % y returns the. // remainder after x is divided by y. // If you divide an even number by 2, the remainder is 0. // If you divide an odd number by 2, the remainder is 1. if ( num % 2 == 0) {

  7. Study with Quizlet and memorize flashcards containing terms like 5.1.6: 2 Through 20 Even, 5.1.7: Divisibility, 5.2.5: Counting 10 to 100 by tens and more.