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7.4.8: Need Help. Here's my code and it works. Not totally sure, but you're checking if 'character' == 'word' , then increment the counter. But, using the examples page... that would be saying.
def count_occurrences(e, d): counter = 0 for checker in e: if (checker == d): counter= counter + 1 return counter print (count_occurrences("elephant", "e"))
I need help with 7.4 Keeping Count. You have to clarify what version of CodeHS you're using though. I'm in Java/Nitro, and I don't see any "keeping count" problem there. Clarifying which version you're using helps save people a bunch of time to help you.
Μεταχειρισμένα τρακτέρ (τρακτεράκια) Kubota από 10Hp έως 50Hp και σας τα παρέχουμε πλήρως ανακατασκευασμένα και με 5 χρόνια γραπτή εγγύηση.
Strings And For Loops/7.4.8 Count Occurrences.py at master · emrgem/CodeHS-Intro_To_Computer_Science-Answers-Python An answer key to the Intro to Computer Science in Python. - emrgem/CodeHS-Intro_To_Computer_Science-Answers-Python
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σχετικά με: kubota traqtorebi 7 4 8 keeping countTry the eBay way-getting what you want doesn't have to be a splurge. Browse Kubota.! We've got your back with eBay money-back guarantee. Enjoy Kubota. you can trust.
