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1. en.wikipedia.org › wiki › V-1_(TV_series)V-1 (TV series) - Wikipedia

   en.wikipedia.org › wiki › V-1_(TV_series)

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   V-1 was a South Korean music television program that aired as a pilot program for Chuseok on tvN, on September 13–15, 2019 at 17:40 (KST). It was hosted by Kang Ho-dong.

2. www.1tv.comПервый канал за рубежом. Прямой эфир. Channel One Russia

   www.1tv.com

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   Все программы. Официальный международный сайт Первого канала. Смотреть онлайн. Channel One Russia official website.

3. www.tvnz.co.nz › livetv › tvnz-2Watch TVNZ 2 - Free Live TV | TVNZ | TVNZ+

   www.tvnz.co.nz › livetv › tvnz-2

   Live the moment with TVNZ 2, New Zealand's home of entertainment. Watch local shows, dramas, comedies and reality TV.

4. www.tvnz.co.nz › livetv › tvnz-1Watch TVNZ 1 - Free Live TV | TVNZ | TVNZ+

   www.tvnz.co.nz › livetv › tvnz-1

   Adult Animation. What's New. Factual. Get into the story with TVNZ 1. Watch local shows, quality dramas and documentaries.

5. ru.wikipedia.org › wiki › TVN_(телеканал,_Польша)TVN (телеканал, Польша) — Википедия

   ru.wikipedia.org › wiki › TVN_(телеканал,_Польша)

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   tvn — польский общенациональный телеканал. Один из крупнейших частных телеканалов Польши. Начал вещание 3 октября 1997 года.

6. en.wikipedia.org › wiki › TvN_(South_Korean_TV_channel)tvN (South Korean TV channel) - Wikipedia

   en.wikipedia.org › wiki › TvN_(South_Korean_TV_channel)

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   News. tvN e-News 9 (an entertainment equivalent of KBS News 9 and JTBC Newsroom); Dramas. tvN dramas are exported to various countries in Asia and the Americas. tvN's highest-rated television series are Queen of Tears, Crash Landing on You, Reply 1988 and Guardian: The Lonely and Great God.The final episode of Queen of Tears recorded a 24.850% nationwide audience share, making it the third ...

7. math.stackexchange.com › questions › 3089062Prove that $Tv_1,...,Tv_n$ is linearly independent in $W$

   math.stackexchange.com › questions › 3089062

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   27 Ιαν 2019 · Prove that $Tv_1,...,Tv_n$ is linearly independent in $W$. I generally follow the solution below: But I don't understand the line "Because $T$ is injective, this implies that $a_1v_1 + ... +a_nv_n = 0$ ".