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27 Δεκ 2019 · for j in range(1,n2): g = n2 % j. print('\n j is {}, g is {}'.format(j, g)) if (f == 0 and g == 0 and f == g): mxcd = f. else: mxcd = "No hay comun divisor". return mxcd. running something like mcd(2,4) lets you know a lot:
24 Ιουν 2012 · The greatest common divisor (GCD) of a and b is the largest number that divides both of them with no remainder. One way to find the GCD of two numbers is Euclid’s algorithm, which is based on the observation that if r is the remainder when a is divided by b , then gcd(a, b) = gcd(b, r) .
2 Μαρ 2024 · A compact one-liner that combines list comprehension, the gcd() function from Python’s math module, and a lambda function to count the common divisors in a single expression. It’s not only concise but also takes advantage of Python’s functional programming capabilities.
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20 Μαρ 2014 · It doesn't mean "define gcd (a,b) to be equal to gcd (b,r)". Instead, gcd(a,b)==gcd(b,r) means: Compare the two results and see if they're equal. Since you're asking to compute gcd(a, b) in order to compute gcd(a, b), you'll get an endless recursion.
15 Φεβ 2016 · >>> numbers = [100, 5, 6] >>> divisors = [count_divisors(number) for number in numbers] >>> for number, divisor_count in zip(numbers, divisors): ... print("{} has {} divisors".format(number, divisor_count)) You can use the built-in function max to search for the maximum on some criteria: >>> max(zip(numbers, divisors), key=itemgetter(1)) (100, 9)
3 Ιαν 2022 · First use Euclid's algorithm to find the greatest common divisor. Then determine the prime factorization of the GCD (if your numbers aren't too large, this can be done by successive divisions). Finally, generate all tuples of multiplicities of the prime factors, from 0 to their value in the GCD and compute the corresponding integer.
