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19 Δεκ 2013 · The formula can be explained like this: The difference in months as output by DATEDIFF(m, ..., ...) Plus the day of the last date divided by the number of days in that month. Minus the day of the first date divided by the number of days in that month.
9 Οκτ 2009 · How can I use DATEDIFF to return the difference between two dates in years, months and days in SQL Server 2005. DATEDIFF (date , date) How to result that: 2 year 3 month 10 day. Can anyone complete this t-sql? ALTER FUNCTION [dbo].[gatYMD](@dstart VARCHAR(50), @dend VARCHAR(50)) RETURNS VARCHAR(50) AS. BEGIN. DECLARE @yy INT. DECLARE @mm INT.
25 Αυγ 2011 · Definition and Usage. The DATEDIFF () function returns the difference between two dates, as an integer. Syntax. DATEDIFF ( interval, date1, date2) Parameter Values. Technical Details. More Examples. Example. Return the difference between two date values, in months: SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Try it Yourself »
30 Δεκ 2022 · Transact-SQL reference for the DATEDIFF function. Returns the numerical difference between a start and end date based on datepart.
The following example illustrates how to use the DATEDIFF() function to calculate the difference in hours between two DATETIME values: SELECT DATEDIFF ( hour , '2015-01-01 01:00:00' , '2015-01-01 03:00:00' ); Code language: SQL (Structured Query Language) ( sql )
To calculate the difference between two dates in years, months, weeks, etc., you use the DATEDIFF() function: DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) ( sql )
You can use the DateDiff function to determine how many specified time intervals exist between two dates. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year.
