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If wrong single reagent, CE = zero Incomplete single reagent (e.g. carbonate) or wrong formula (e.g.NaCO3) loses reagent mark, but mark on. For “no reaction” allow “nothing”. Different reagents. If different tests on E and F; both reagents and any follow on chemistry must be correct for first (reagent) mark.
1H & 13C NMR SPECTROSCOPY QUESTIONS. with molecular formula C6H14O are shown. The relative integration values for the NMR peaks are shown on Figure 2. Deduce the structure of compound R by analysing Figure 1 and Figure 2. Explain each stage in your deductions. Use Table A and Table B on the Data Sheet
Chapter 13: Nuclear Magnetic Resonance (NMR) Spectroscopy direct observation of the H’s and C’s of a molecules Nuclei are positively charged and spin on an axis; they create a tiny magnetic field + + Not all nuclei are suitable for NMR. 1H and 13C are the most important NMR active nuclei in organic chemistry Natural Abundance 1H 99.9% 13C 1.1%
We can examine the nuclear magnetic properties of carbon atoms in a molecule to learn about a molecules structure. Most carbons are 12C; 12C has an even number of protons and neutrons and cannot be observed by NMR techniques.
13C-NMR Spectroscopy Worksheets (Spring 2016) of the Group Members: __________________________ Answer questions (1)-(4) (part I) below in lab. Answer questions (5) and (6) (part II) below in the computer lab. You will work in pairs on this assignment and do the entire assignment in the worksheets provided, one isomer per worksheet. .
13C NMR spectroscopy shows peaks for each of the different chemical environments of the carbon atom in a molecule. The environment of a carbon atom can be determined by looking at the sequence of bonds the carbon atom has to other atoms.
(c) The C-13 NMR spectrum of compound A has four peaks. Identify the structure of A. Explain your reasoning by labelling the different carbon environments in all the structures drawn in part (ii).
