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Solutions: Exploring Blackbody Radiation using the PhET Simulation. Temperature = 4800K: 1. What would you say is the color of the EM “blackbody” source shown at the top as a star burst? off-white / yellow. 2. Are all three spectral colors - blue, green, red – needed to produce this color? yes. 3.
In this lab you will use an incandescent light bulb and a prism spectrometer to measure the blackbody spectrum. Although a light bulb is not a blackbody (it emits much more radiation than it absorb!) it is a good approximation of a grey body: an object that emits a fraction of the blackbody spectrum with the same frequency distribution.
The radiation represents a conversion of a body’s thermal energy into electromagnetic energy, and is therefore called thermal radiation. Conversely all matter absorbs electromagnetic radiation to some degree. An object that absorbs all radiation falling on it at all wavelengths is called a blackbody.
A perfect black body is an object that absorbs all of the radiation that it comes in contact with. This means that it does not transmit or reflect any radiation.
Blackbody Radiation. Experiment objectives: explore radiation from objects at certain temperatures, commonly known as \blackbody radiation"; make measurements testing the Stefan-Boltzmann law; measure the inverse-square law for thermal radiation.
To begin analyzing heat radiation, we need to be specific about the body doing the radiating: the simplest possible case is an idealized body which is a perfect absorber, and therefore also (from the above argument) a perfect emitter. For obvious reasons, this is called a “black body”.
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