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  1. After studying this chapter you should. be familiar with cartesian and parametric equations of a curve; be able to sketch simple curves; be able to recognise the rectangular hyperbola; be able to use the general equation of a circle; be able to differentiate simple functions when expressed parametrically.

  2. This chapter contains a selection of useful cheatsheets. For updates check here: https://www.rstudio.com/resources/. To download the pdf of a cheatsheet, just click on the link in the figure caption.

  3. The Cartesian equation is a way to represent geometric objects such as lines, circles, and curves using algebraic expressions. It involves defining a coordinate system with two perpendicular axes (x and y), and representing points in the plane as ordered pairs of numbers (x, y).

  4. These examples are curves given by a Cartesian equation: f(x;y) = c where f: R2!R is a function in 2 variables: Put di erently, the curve is given as a level set C= f(x;y) 2R2 jf(x;y) = cg of the di erentiable function f. In our examples we have f(x;y) = y 2x, f(x;y) = x2+y2 and f(x;y) = y x2 respectively, and all curves are plane curves. If we ...

  5. 4 Αυγ 2023 · What are parametric equations? Graphs are usually described by a Cartesian equation. The equation involves x and y only; Equations like this can sometimes be rearranged into the form, y = f(x) In parametric equations both x and y are dependent on a third variable This is called a parameter; t and θ are often used as parameters; A common ...

  6. Eliminate the parameter \(t\) to find a Cartesian equation of the curve. Partition the interval \(I=[-3,3]\) into \(t_0=-3, t_1=-2, t_2=-1, \ldots, t_7=3\) and evaluate \((x(t_i), y(t_i))\) and plot points.

  7. we can solve t = y 2. Plug it into x = t2 3, we get the Cartesian equation x =(y 2)2 3. From this equation, we know it is a parabola with vertex (3,2) and open to right. Then you need to figure out which part on this parabola corresponds to the parametric curve for t 2 [3,3]. As we did in the class, this is y 2 [1,5] (or you can also write x 6 ...