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x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)
Explanation: Reduce the greatest common factor on both sides of the equation: t-1=5 Rearrange unknown terms to the left side of the equation: t=5-1 Calculate the first two terms: t=4+4 Answer: t=4 SHOW LESS
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2(t+1)=10 One solution was found : t = 4 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...
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What is the answer to 2(t+1)=10 ? The answer to 2(t+1)=10 is t=4; Solve for t: 2(t+1)=10; The solution is t=4
