Αποτελέσματα Αναζήτησης
10 Ιουλ 2012 · The DATEDIFF function is use to calculate the number of days between the required date. Example if you are diff current date from given date in string format. SELECT * , DATEDIFF(CURDATE(),STR_TO_DATE('01/11/2017', '%m/%d/%Y')) AS days FROM consignments WHERE code = '1610000154'.
25 Αυγ 2011 · Definition and Usage. The DATEDIFF () function returns the difference between two dates, as an integer. Syntax. DATEDIFF (interval, date1, date2) Parameter Values. Technical Details. More Examples. Example. Return the difference between two date values, in months: SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Try it Yourself »
To calculate the difference between two dates in years, months, weeks, etc., you use the DATEDIFF() function: DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date.
The following example illustrates how to use the DATEDIFF() function to calculate the difference in hours between two DATETIME values: SELECT DATEDIFF ( hour , '2015-01-01 01:00:00' , '2015-01-01 03:00:00' ); Code language: SQL (Structured Query Language) ( sql )
28 Οκτ 2024 · Transact-SQL reference for the DATEDIFF function. Returns the numerical difference between a start and end date based on datepart.
24 Απρ 2023 · For example, the following query is used to find all records where the year in the DateColumn column is 2009: SELECT * . FROM [StackOverflow2010].[dbo].[Posts] WHERE DATEPART(year, CreationDate) = 2009; Similarly, you can use DATEPART to extract and compare other date parts, such as month or day.
10 Φεβ 2022 · The DATEDIFF function returns the difference between two dates according to the datepart specified: such as year, day, month, etc. Syntax DATEDIFF(datepart, date1, date2)
