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The substitution you should make is that $mg = \frac{GM_{\rm E}m}{R^2}$ where $g$ is the value of the gravitational field strength at a distance $R$ from the centre of the Earth. Note that the value of $g$ is not constant.
PE grav = m *• g • h In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.
In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. [1][2] The term potential energy was introduced by the 19th-century Scottish engineer and physicist William Rankine, [3][4][5] although it has links to the ancient Greek ph...
The change in gravitational potential energy, ΔPE g, is ΔPE g = mgh, with h being the increase in height and g the acceleration due to gravity. The gravitational potential energy of an object near Earth’s surface is due to its position in the mass-Earth system.
16 Αυγ 2021 · The change in gravitational potential energy \(\Delta PE_g\), is \(\Delta PE_g = mgh\), with \(h\) being the increase in height and \(g\) the acceleration due to gravity. The gravitational potential energy of an object near Earth’s surface is due to its position in the mass-Earth system.
30 Οκτ 2024 · Gravitational Potential Energy Equation. The gravitational potential energy, Ep, of an object can be calculated using the equation: Ep = m × g × h. Where: Ep = gravitational potential energy, in joules (J) m = mass, in kilograms (kg) g = gravitational field strength in newtons per kilogram (N/kg) h = height in metres (m)
Starting from the escape velocity formula, derive an equation for the radius of the event horizon in terms of m (the mass of the black hole), G (the gravitational constant), and c (the speed of light).
