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Student Answer Keys. (See related pages) Click the links below to view the Student Answer Keys in Microsoft Word format. Answer Key - Chapter 01 (23.0K) Answer Key - Chapter 02 (20.0K) Answer Key - Chapter 03 (44.0K)
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Gravitational potential energy depends upon height (PE=m*g*h). The PE is a minimum when the height is a minimum. Position B is the lowest position in the diagram.
PE grav = mass • g • height PE grav = m *• g • h. In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.
In this lesson, we will learn how to calculate changes in the energy of an object in a gravitational field using the definition of the gravitational potential energy, E = mgh.
The substitution you should make is that $mg = \frac{GM_{\rm E}m}{R^2}$ where $g$ is the value of the gravitational field strength at a distance $R$ from the centre of the Earth. Note that the value of $g$ is not constant.
Explain gravitational potential energy in terms of work done against gravity. Show that the gravitational potential energy of an object of mass m at height h on Earth is given by PEg = mgh. Show how knowledge of the potential energy as a function of position can be used to simplify calculations and explain physical phenomena.
Kinetic and potential energy are both proportional to the mass of the object. In a situation where KE = PE, we know that mgh = (1/2)mv 2. Dividing both sides by m and rearranging, we get the relationship 2gh = v 2.
