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The force of gravity (also known as weight) acts in a downward direction; yet the normal force acts in a direction perpendicular to the surface (in fact, normal means "perpendicular"). The Abnormal Normal Force. The first peculiarity of inclined plane problems is that the normal force is not directed in the direction that we are accustomed to ...
The normal force is always perpendicular to the surface, and since there is no motion perpendicular to the surface, the normal force should equal the component of the skier’s weight perpendicular to the slope.
What happens to forces as the incline increases? Weight (F W) stays the same; Normal force (F N) decreases; Parallel force (F ⸗) increases
Normal Force: Remember that a normal force F N is always perpendicular to the surface that you are on. Since this surface is slanted at a bit of an angle, the normal force will also point at a bit of an angle.
29 Ιουλ 2024 · On an inclined surface (assuming that the object doesn't slide down), the weight of the object is supported by both the normal force and friction. The gravitational force of the object is not opposite and equal to the normal force, but one of the force of gravity's vector's components is.
When objects rest on a non-accelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object: \[ N = mg \] When objects rest on an inclined plane that makes an angle \(\theta \) with the horizontal surface, the weight of the object can be resolved into components that act perpendicular \((w_{\perp})\) and ...
for the direction perpendicular to the plane. Of course, since there is no motion in this direction, \(a_y\) is zero. This gives us immediately the value of the normal force: \[ F^{n}=F^{g} \cos \theta=m g \cos \theta \label{eq:8.17} \] since \(F^g = mg\).
