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  1. 15 Μαρ 2010 · If you have lots of records to update, use join, so something like: update (select bonus from employee_bonus b inner join employees e on b.employee_id = e.employee_id where e.bonus_eligible = 'N') t set t.bonus = 0; See this link for more details. http://geekswithblogs.net/WillSmith/archive/2008/06/18/oracle-update-with-join-again.aspx.

  2. 27 Δεκ 2023 · Before diving into complex examples, let's understand the basic syntax of an update with a join operation in Oracle: sql UPDATE table1 SET table1.target_column = (SELECT table2.source_column FROM table2 WHERE table1.join_column = table2.join_column) WHERE EXISTS (SELECT 1 FROM table2 WHERE table1.join_column = table2.join_column); In the above ...

  3. 24 Μαΐ 2017 · Usually, when you need to join multiple tables in an UPDATE, MERGE is the solution.

  4. 21 Σεπ 2017 · update (select a.category as defaultcategory from a left join b on b.xx_id = a.xx_id left join c on c.zz_id = b.zz_id left join d on d.yy_id = c.yy_id where d.yy_id = ‘123’) dc set dc.defaultcategory = (select kk_id from cc where name = 'NNN') - create table statements for all your tables.

  5. 5 Απρ 2023 · Now we update the data in T1 using a join to the T2 table. We want to update the T1.CODE and T1.DESCRIPTION values, using the values from T2.CODE and T2.DESCRIPTION using a join in the ID value. update t1 a set a.code = b.code, a.description = b.description from t2 b where a.id = b.id and b.id <= 5;

  6. The following statement updates three columns, FLIGHT_NUMBER, FLIGHT_DURATION, and OPERATING_CARRIER_CODE, in a single row of the FLIGHTS table. The row to be updated is identified using the WEHERE clause. A SELECT statement displays the updated content for the FLIGHTS table for verification.

  7. 3 Μαΐ 2016 · I want to know if there is a way it can be done by joins. For example, I tried the following queries but they fail. SQL> update ages set age = age + 1 from ages, names where ages.id = names.id and names.name = 'Sally'; update ages set age = age + 1 from ages, names where ages.id = names.id and names.name = 'Sally'.

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