Αποτελέσματα Αναζήτησης
27 Αυγ 2015 · I'm going to rewrite this proof by dividing by all powers of ten and what not. The proof essentially goes: $$ \frac{0}{0}=\frac{2\cdot 0}{1\cdot 0}=\frac{2}{1}$$ The problem is in the first line, when you write $\frac{0}{0}$, which is undefined.
1 Δεκ 2015 · From this standpoint, what you've really proved is that if $\frac{0}{0}$ is anything except $0$, then the law $2\frac{0}{0} = \frac{2 \cdot 0}{0}$ cannot hold. Therefore, the law: $a\frac{b}{c} = \frac{ab}{c}$ cannot hold, either. This suggests that simply defining $\frac{0}{0}=0$ might actually be a good idea. Unfortunately, this breaks ...
10 Δεκ 2018 · Let's say that 0/0 followed that old algebraic rule that anything divided by itself is 1. Then you can do the following proof: 0/0 = 1. Now multiply both sides by any number n. n * (0/0) = n * 1. (n*0)/0 = n . (0/0) = n . 1 = n . So we just proved that all other numbers n are equal to 1! So 0/0 can't be equal to 1.
11 Νοε 2017 · In practice, division by #0# is (almost) always undefined and #0/0# is an indeterminate form. The true version of the premise assumed above might be "Any non-zero number divided by itself is #1# ". Answer link
In lay terms, evaluating 0/0 is asking "what number, when multiplied by zero, gives zero". Since the answer to this is "any number", it cannot be defined as a specific value. The accepted definition of division on the natural numbers is something like:
We can say that zero divided by 1 equals zero and we can also say that this is "defined" as well. Our next example is going to be 1 divided by zero. And a lot of people like to guess that it would be zero. So, let's try that out. We take our "b" which is zero and multiply it by our "c" which is zero.
18 Σεπ 2016 · While division by 0 is undefined in most cases, in this specific scenario of 0/0 = 2, we are not dividing by 0 itself. Instead, we are approaching 0 from both the numerator and denominator, which results in a limit of 2.
