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Design an experiment to accurately determine the empirical formula of a given hydrate. Predict how experimental factors will impact the accuracy and precision of results. Calculate the molar ratio of water to anhydrous solid to determine the hydrate's formula.
- 1.7: Experiment 6
Design an experiment to accurately determine the empirical...
- 1.7: Experiment 6
Design an experiment to accurately determine the empirical formula of a given hydrate. Predict how experimental factors will impact the accuracy and precision of results. Calculate the molar ratio of water to anhydrous solid to determine the hydrate's formula.
The formula of a hydrate consists of the formula of the anhydrous (without water) compound followed by a dot, then the number of molecules of water that crystallize with one formula unit of the compound, then the formula of water.
7 Αυγ 2011 · The formula of the anhydrous salt is known, so its formula weight can be calculated. The weight of the material in the crucible after heating can then be used to determine the number of moles of the anhydrous salt. Comparing these two mole numbers gives the complete formula of the hydrated salt.
Formula of a Hydrated Introduction. Sometimes salts combine chemically with water and form hydrates in which a definite number of water molecules combine with the ions of a salt to form a crystal. Although chemically bound, this water of hydration maintains its characteristic composition in much the same manner as radicals do.
7 Ιουν 2024 · The degree of hydration can be calculated from experimental results: The mass of the hydrated salt must be measured before heating; The salt is then heated until it reaches a constant mass; The two mass values can be used to calculate the number of moles of water in the hydrated salt - known as the water of crystallisation
What is the formula of the hydrate? Solution: 1) Determine mass of water driven off: 15.67 − 7.58 = 8.09 g of water. 2) Determine moles of MgCO 3 and water: MgCO 3 ---> 7.58 g / 84.313 g/mol = 0.0899 mol H 2 O ---> 8.09 g / 18.015 g/mol = 0.449 mol.
