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@OmarIthawi that is just silly. It's a proof-of-concept with awkward API, inefficient implementation. I think it is better to consider libraries on their own merits, instead of trying to deduce quality out of its authors visibility -- Doug has achieved many things, but that does not really change qualities of the particular lib. 10 years ago it was the only game in town, but since then there ...
In principal, they are both just transmitting data. The only difference is how you process it in the server. If you have only few key-value pair then a normal POST parameter with key1=value1, key2=value2, etc is probably enough, but once your data is more complex and especially containing complex structure (nested object, arrays) you would want to start consider using JS
5 Νοε 2010 · If you are using a Java API for JSON Processing (JSR-353) implementation then you can specify the JsonGenerator.PRETTY_PRINTING property when you create a JsonGeneratorFactory. The following example has been originally published on my blog post. import java.util.*; import javax.json.Json; import javax.json.stream.*;
16 Ιαν 2012 · I got here looking for a nice way to write rest endpoint tests with a fluent json builder. In my case I used JSONObject to construct a specialized builder.
16 Φεβ 2015 · Even with the most recent schema available, JSON <-> Protobuf conversion may be lossy in the presence of imprecise floating-point values and similar corner cases. Protobufs actually have (slightly) stronger backwards-compatibility guarantees than JSON. Like with JSON, if you add a new field, old clients will ignore it.
7 Ιουν 2012 · I want to read this JSON file with java using json simple library. My JSON file looks like this
11 Ιουν 2010 · When creating JSON data manually, how should I escape string fields? Should I use something like Apache Commons Lang's StringEscapeUtilities.escapeHtml, StringEscapeUtilities.escapeXml, or should I...
21 Δεκ 2022 · Get a value from Json Object in java. 0. I want to extract a value from a json. Hot Network ...
If you need convert JSONobject to yaml (string). you need. Firstly get json string, then map, after that you can convert to yaml.
30 Νοε 2010 · I wanted to add an updated answer here since (somewhat) recent updates to the JDK have made it a bit easier to read the contents of an HTTP URL. Like others have said, you'll still need to use a JSON library to do the parsing, since the JDK doesn't currently contain one. Here are a few of the most commonly used JSON libraries for Java: org.JSON
