Αποτελέσματα Αναζήτησης
8 Νοε 2012 · I have always wondered why the energy of a photon in vacuum is equal to E = pc (where p is the momentum of the photon, and c is the speed of light in vacuum) and not E = 1/2 pv (where for a photon v = c) as is the case for the kinetic energy of any moving mass.
In general, when converting from base units (m, l, g, etc) or derived units (m2,m3, m/s, Hz, N, J, V, etc) to a multiple greater (kilo, mega, giga, or tera) than the base or derived unit- then divide by the factor. For example: 10m = 10/1000km = 1/100 km = .01km.
The equation [latex]\boldsymbol{E^2 = (pc)^2 + (mc^2)^2}[/latex] relates the relativistic total energy [latex]\boldsymbol{E}[/latex] and the relativistic momentum [latex]\boldsymbol{p}[/latex]. At extremely high velocities, the rest energy [latex]\boldsymbol{mc^2}[/latex] becomes negligible, and [latex]\boldsymbol{E = pc}[/latex].
In a reference frame where the system is moving, its relativistic energy and relativistic mass (instead of rest mass) obey the same formula. The formula defines the energy E of a particle in its rest frame as the product of mass (m) with the speed of light squared (c2).
The work-energy theorem states that the net work \(W_{net} \) on a system changes its kinetic energy, \(W_{net} = \frac{1}{2}mv^2 - \frac{1}{2}mv_0^2\). Glossary net work
physics formulas list, that will act as a ready reference, when you are solving physics problems. You can even use this list, for a quick revision before an exam.
11 Αυγ 2021 · Choosing ε = − u2 / c2 and n = − 1 2 leads to the conclusion that γ at nonrelativistic speeds, where ε = u / c is small, satisfies. γ = (1 − u2 / c2) − 1 / 2 ≈ 1 + 1 2 (u2 c2).
