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  1. www.integral-table.com › downloads › single-page-integral-tableTable of Integrals

    Integrals with Trigonometric Functions Z sinaxdx= 1 a cosax (63) Z sin2 axdx= x 2 sin2ax 4a (64) Z sinn axdx= 1 a cosax 2F 1 1 2; 1 n 2; 3 2;cos2 ax (65) Z sin3 axdx= 3cosax 4a + cos3ax 12a (66) Z cosaxdx=

  2. 7 Σεπ 2022 · Basic Integrals. 1. \(\quad \displaystyle ∫u^n\,du=\frac{u^{n+1}}{n+1}+C,\quad n≠−1\) 2. \(\quad \displaystyle ∫\frac{du}{u} =\ln |u|+C\) 3. \(\quad \displaystyle ∫e^u\,du=e^u+C\) 4. \(\quad \displaystyle ∫a^u\,du=\frac{a^u}{\ln a}+C\) 5. \(\quad \displaystyle ∫\sin u\,du=−\cos u+C\) 6. \(\quad \displaystyle ∫\cos u\,du=\sin u+C\)

  3. www.integral-table.com › downloads › integral-tableTable of Basic Integrals

    Table of Basic Integrals Basic Forms (1) Z xndx= 1 n+ 1 xn+1; n6= 1 (2) Z 1 x dx= lnjxj (3) Z udv= uv Z vdu (4) Z 1 ax+ b dx= 1 a lnjax+ bj Integrals of Rational Functions (5) Z 1 (x+ a)2 dx= 1 x+ a (6) Z ... Integrals with Trigonometric Functions (71) Z sinaxdx= 1 a cosax (72) Z sin2 axdx= x 2 sin2ax 4a (73) Z sin3 axdx= 3cosax 4a + cos3ax 12a ...

  4. www.integral-table.com › downloads › Basic-Integral-TableTable of Basic Integrals1

    Table of Basic Integrals1 (1) Z xn dx = 1 n+1 xn+1; n 6= 1 (2) Z 1 x dx = lnjxj (3) Z u dv = uv Z vdu (4) Z e xdx = e (5) Z ax dx = 1 lna ax (6) Z lnxdx = xlnx x (7) Z sinxdx = cosx (8) Z cosxdx = sinx (9) Z ... CSUN, Integrals, Table of Integrals, Math 280, Math 351, Differential Equations Created Date:

  5. Table of Integrals 1. Z ur du = ur+1 r +1 +C, r 6=−1 2. Z 1 u du =ln|u|+C 3. Z eu du = eu +C 4. Z sinudu= − cosu+C 5. Z ... Basic Trigonometric Identities 1. sin2 θ +cos2 θ =1 2. 1+tan2 θ = sec2 ... Title: int-table.dvi Created Date: 9/15/2009 12:30:20 PM ...

  6. 5.2 The Definite Integral; 5.3 The Fundamental Theorem of Calculus; 5.4 Integration Formulas and the Net Change Theorem; 5.5 Substitution; 5.6 Integrals Involving Exponential and Logarithmic Functions; 5.7 Integrals Resulting in Inverse Trigonometric Functions

  7. Integration by parts: u dv = uvv du + C Partial Fractions: to integrate a function like ax+b (x+c)(x+d): Write ax+b (x+c)(x+d) = A (x+c) + B (x+d) = A(x+d)+B(x+c) (x+c)(x+d), so ax+b = A(x+d)+B(x+c)=(A+B)x+(Ad+Bc), so a = A+B and b = Ad+Bc; solve for A and B. The approach for more general denomenator can be found in nearly any calculus ...

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