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You now know the number of moles of each substance needed in a theoretical perfect reaction. If you want to know the number of grams needed of each substance, you can multiply by the molar mass of each substance: NaOH = 2.10 mol * 39.997 g/mol = 83.9937g. Mg (OH)2 = 1.05 mol * 58.319 g/mol = 61.23495g.
30 Ιαν 2024 · Substitute the known values to calculate the molarity: molarity = 5 / (1.2 × 36.46) = 0.114 mol/l = 0.114 M. You can also use this molarity calculator to find the mass concentration or molar mass. Simply type in the remaining values and watch it do all the work for you.
17 Ιουλ 2024 · Multiply the moles of the limiting reagent by the stoichiometry of carbon dioxide in the reaction to give the moles of CO 2 produced. Multiply the moles of CO 2 produced by 44, the molecular weight of CO 2, to get the theoretical yield of your reaction.
For example, one mole of carbon-12 atoms weighs 12 grams, while one mole of water (H2O) molecules weighs 18 grams (2 hydrogen atoms weigh 1 gram each, and 1 oxygen atom weighs 16 grams). This relationship between moles and mass is known as the molar mass.
How many moles of oxygen are required to completely react with 16.1 grams of magnesium metal according to the equation: 2 Mg(s) + O2(g) → 2 MgO(s) ?
If we were to ask how many grams of elemental iron will be formed by the reduction of 1.0 grams of iron (III) oxide, we would simply use the molar stoichiometry to determine the number of moles of iron that would be produced, and then convert moles into grams using the known molar mass.
Flowchart of steps in stoichiometric calculations. Step 1: grams of A is converted to moles by multiplying by the inverse of the molar mass. Step 2: moles of A is converted to moles of B by multiplying by the molar ratio. Step 3: moles of B is converted to grams of B by the molar mass.
