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  1. 7 Οκτ 2020 · For a universe that is flat, has matter and a cosmological constant, we can write the Friedmann equation in the following way: $$\frac{H^{2}}{H^{2}_{0}} = \frac{\Omega_{m,0}}{a^{3}} + (1 - \Omega_{m,0})$$

  2. 11 Αυγ 2024 · The Friedmann equation embodies the essence of the Einstein equation: matter and energy affect how spacetime bends. In general relativity, it is not only matter that produces curvature, but any sort of energy.

  3. en.wikipedia.org › wiki › Big_CrunchBig Crunch - Wikipedia

    The Big Crunch is a hypothetical scenario for the ultimate fate of the universe, in which the expansion of the universe eventually reverses and the universe recollapses, ultimately causing the cosmic scale factor to reach zero, an event potentially followed by a reformation of the universe starting with another Big Bang.

  4. Each equation contains four variables. The variables include acceleration (a), time (t), displacement (d), final velocity (vf), and initial velocity (vi). If values of three variables are known, then the others can be calculated using the equations.

  5. 22 Δεκ 2014 · The Big Crunch is a prediction of the FLRW metric when the matter/energy density is above the critical value i.e. a closed universe. The FLRW metric gives us the scale factor of the universe as a function of comoving time, and for a closed universe the scale factor increases smoothly with time from zero at the Big Bang, through a maximum and ...

  6. 29 Απρ 2022 · Kinematic Equation 1: Review and Examples. To learn how to solve problems with these new, longer equations, we’ll start with v=v_{0}+at. This kinematic equation shows a relationship between final velocity, initial velocity, constant acceleration, and time. We will explore this equation as it relates to physics word problems.

  7. phys.libretexts.org › Courses › University_of_California_Davis8.2: Kinematics - Physics LibreTexts

    Since position depends quadratically on time, the quadratic equation is often needed to solve for time. Rewriting Equation \ref{xt} in the form of a quadratic equation we get: \[\frac{1}{2}gt^2+v_ot+(x_o-x_f)=0\] Applying the quadratic equation to solve for time: \[t=\frac{-v_o\pm\sqrt{v_o^2-2g(x_o-x_f)}}{g}\]

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