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Even though the net force is zero, the object might not be in static equilibrium. Here is a case (two forces acting on a bar) where the net force F is zero, but the forces cause the object to rotate: In order to guarantee static equilibrium, we must have. net force = 0 AND. net torque = 0. F.
K = K 2 K 1 = X ~F ~s 1.2 Relationship Between Kinetic Energy and Momentum As you can see from the above equation, the P~ F (the net force) forms a rela-tionship between the change in momentum and the change in kinetic energy. The relationship between the kinetic energy (1 2 mv 2) and the momentum (mv) is: K = p2 2m or K = p~p~ 2m (7) dK = 1 2m ...
Rotational Motion. We are going to consider the motion of a rigid body about a fixed axis of rotation. The angle of rotation is measured in radians: (rads) . s. (dimensionless) r. s . Notice that for a given angle , the ratio s/r is independent of the size of the circle.
F=ma for rotation: t=Ia. Use F=ma, t=Ia to solve for a, a, tension, time. Use conservation of energy to solve for speed. Can choose any axis or pivot around which to compute torques. Trick of the trade: If there is a force on the pivot, the torque it produces is 0!
solution of these equations such that x(t 0) = X in and x(t 0 + ∆t) = X f, where X in and X f are, respectively, the (initial) height of your hand when the baseball leaves it, and the (final) height of your hand when you catch the ball.1 With the advent of the computer, it is often easier to solve equations of motion
This textbook covers all the standard introductory topics in classical mechanics, including Newton’s laws, oscillations, energy, momentum, angular momentum, planetary motion, and special relativity.
Stretching a Spring. The unloaded spring has a length L0. Hang a weight of mass m on it and it stretches to a new length L. Δs=L-L0 vs. the applied force Fsp=mg. We find that Fsp=kΔs, where. k is the “spring constant”.
