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Given, 1 + 4 + 7 + 10..... + x = 287. We need to find the value of x, First-term, a = 1. Common difference, d = 4-1 = 3. S n = 287. Using the formula, S n = n 2 (2 a + (n − 1) d) 287 = n 2 (2 × 1 + (n-1) 3) 287 = n 2 (2 + 3 n-3) 574 = n (3 n-1) 574 = 3 n 2-n. 3 n 2-n-574 = 0. 3 n 2-42 n + 41 n-574 = 0. 3 n (n-14) + 41 (n-14) = 0 (3 n + 41 ...
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Then, x = Suppose the angles of a triangle are (a − d), a , (a + d) such that , (a + d) >a > (a − d). Write the formula of the sum of first n terms for an A.P.
17 Μαρ 2020 · Here 1, 4, 7, 10, ... x is an A.P. With first term a = 1 and common difference d = 3. Let there be n terms in the A.P. Then, x = nth term . x = 1 + (n – 1) × 3 = 3n – 2 ...(i) Now, 1 + 4 + 7 + 10 + ... + x = 287. Putting n = 14 in eqn (i), we get . x = 3 × 14 – 2 . x = 40
On solving the equation 1 + 4 + 7 + 10 +...+ x =287, the value of x is 40 ☛ Related Questions: Find the sum of those integers from 1 to 500 which are multiples of 2 as well as of 5
For example displaystyle (x-1) (x-2) and displaystylex²-3x+2 are two polynomial expressions that represent the same polynomial; so, one has the equality displaystyle (x-1) (x-2)=x²-3x+2.
