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We demonstrate it here to solve the following equation: \(\frac{3}{2}-\frac{9}{2 x}=\frac{3}{5}\) \[\begin{array} \text{Find the LCM of all denominators in the equation} & 10x \\ \text{Multiply every fraction (both LHS and RHS) by the LCM} & 10 x \cdot \frac{3}{2}-10 x \cdot \frac{9}{2 x}=10 x \cdot \frac{3}{5} \\ & \frac{10 x \cdot 3}{2}-\frac ...
Gold is extracted from its ores by treatment with an aqueous cyanide solution, which causes a reaction that forms the soluble [Au(CN) 2] − ion. Gold is then recovered by reduction with metallic zinc according to the following equation: \[ Zn(s) + 2[Au(CN)_2]^-(aq) \rightarrow [Zn(CN)_4]^{2-}(aq) + 2Au(s) \nonumber \]
For these fractions the numerator is greater than the denominator. Each fractional value can have many different, equivalent forms, for example 1 = 22 = −5 −5 = … 1 = 2 2 = − 5 − 5 = …. In order to determine whether two fractions are equivalent we can use the fundamental principle of fractions.
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11 Μαρ 2023 · What is the volume of gold (D = 19.32 g / cm 3) in 100 cm 3 of the ore? Answer. The volume of 100 g of ore is \(\text{V} = \dfrac{m}{D} = \dfrac{100 g}{8.25 g/cm^3} = \text{12.12 cm}^3\) The mass of gold in this volume is \(\text{m} = \text{V} \times \text{C} = \text{12.12 cm}^3 \times \text{0.060 g}/cm^3 = \text{0.727 g}\) The volume of gold =
a = √(φ²/(1 + φ²)) = 0.850651. Compute the length of side b with the following formula: b = a/φ = 0.525731. That's it! This golden ratio calculator helps you to find the lengths of the segments which form the beautiful, divine golden ratio.
All decimals can be converted to a fraction and/or mixed number. 1. Write the decimal as a fraction with a denominator of 1. Examples: 2. Multiply the numerator and denominator by a power of ten to make the decimal a whole number. 3. Reduce if possible. Remember to change all improper fractions to a mixed number. Cannot be reduced 2.
