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Learn how to solve logarithmic equations in two (2) ways. One way by setting the argument equal to each other, and the other way by converting it as an exponential.
- Logarithm Rules
Rules or Laws of Logarithms. In this lesson, you’ll be...
- Condensing Logarithms
The difference between logarithmic expressions implies the...
- Logarithm Rules
16 Νοε 2022 · Solve each of the following equations. Here is a set of practice problems to accompany the Solving Logarithm Equations section of the Exponential and Logarithm Functions chapter of the notes for Paul Dawkins Algebra course at Lamar University.
When asked to solve a logarithmic equation such as or the first thing we need to decide is how to solve the problem. Some logarithmic problems are solved by simply dropping the logarithms while others are solved by rewriting the logarithmic problem in exponential form.
This topic introduces logarithms and exponential equations. Logarithms are used to solve exponential equations, and so are used along with exponential functions when modelling growth and decay. The logarithmic function is an important mathematical function and you will meet it again if you study calculus.
16 Νοε 2022 · In this section we will discuss a couple of methods for solving equations that contain logarithms. Also, as we’ll see, with one of the methods we will need to be careful of the results of the method as it is always possible that the method gives values that are, in fact, not solutions to the equation.
Use like bases to solve exponential equations. Use logarithms to solve exponential equations. Use the definition of a logarithm to solve logarithmic equations. Use the one-to-one property of logarithms to solve logarithmic equations. Solve applied problems involving exponential and logarithmic equations.
Let's look at an example to see how we'll use this to solve equations: Example Solve for \(x\) \[\log _{2} x+\log _{2}(x-4)=2 \] The first thing we can do here is to combine the two logarithmic statements into one. since \(\log _{b}(M * N)=\log _{b} M+\log _{b} N,\) then \(\log _{2} x+\log _{2}(x-4)=\log _{2}[x(x-4)]\) \[\begin{aligned}
