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The isset() function checks whether a variable is set, which means that it has to be declared and is not NULL. This function returns true if the variable exists and is not NULL, otherwise it returns false.
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5 Νοε 2013 · I know it can be fixed by using if(isset()), but I have no idea how to place this on the correct matter in this $query line. Tried a lot, but can't get it right. <?php $query = mysql_query("SELECT `id` FROM `place` WHERE `placeno` = '".$_SESSION['placeno'.$i]."'
isset — Determine if a variable is declared and is different than null. Determine if a variable is considered set, this means if a variable is declared and is different than null. If a variable has been unset with the unset () function, it is no longer considered to be set.
I want to compose a condition like echo isset($row['ref']) ? $row['ref']:'Unknown'; which will show Unknown word if echo $row['ref']; returns empty result. Thanks in advance.
24 Σεπ 2024 · The isset() function in PHP checks whether a variable is declared and not NULL. It returns true if the variable exists and has a non-NULL value, and false otherwise, without modifying the variable. Syntax bool isset( mixed $var [, mixed $... ] ) Parameters: This function accept one or more parameter as mentioned above and described below:
7 Σεπ 2023 · Learn how to use isset () function in PHP to check if a variable has been declared, or is considered declared. See examples of using isset () and scenarios when isset () will not work.
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