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20 Νοε 2019 · You can solve this in a single pass (O(n)) using a HashSet, which has O(1) put and lookup time. Each element is already in the set, in which case it gets removed and the pair counter is incremented, or it's not, in which case you add it:
Find unique pair of strings using java Hashset.
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Today you will learn how to use sets in java by solving this problem. You are given pairs of strings. Two pairs (a, b) and (c, d) are identical if a = c and b = d. That also implies (a, b) is not same as (b, a). After taking each pair as input, you need to print number of unique pairs you currently have.
12 Μαρ 2024 · Master HashSet in Java with exercises & solutions. Learn insertion, iteration, conversion, comparison, and more. Boost your Java skills now!.
I've looked through several solutions and I'm quite surprised. If the problem involves handling pairs and they're already split into two arrays, why combine them back into a single string? Instead, there's a more elegant approach using the SimpleEntry class. You can simply use . Set<AbstractMap.SimpleEntry<String, String>> uniquePairs = new ...
