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  1. 27 Μαρ 2021 · Explain on the basis of the kinetic theory of gases. Answer: On reducing the volume, the space for the given number of molecules of the gas decreases i.e. no. of molecules per unit volume increases.

  2. Explain the concept of the kinetic theory of gases covered in Chapter 13 of NCERT Solutions for Class 11 Physics. The kinetic theory of gases is a theoretical model that describes the molecular composition of the gas in terms of a large number of submicroscopic particles, which include atoms and molecules.

  3. 2. Derive the Boyle's law using kinetic theory of gases? Ans: With the temperature constant, Boyle's law states that the volume of a given quantity of gas is inversely proportional to the pressure P, i.e. PV = constant. The pressure exerted by a gas is now given by the kinetic theory of gases. P Pressure V Volume V Average Velocity

  4. Chapter 13 of Class 11 Physics discusses Kinetic Theory. Some of the Important Questions for Class 11 Physics Chapter 13 are asked from atomic theory, the gas laws, the Boltzmann constant, the Avogadro number, the postulates of the kinetic theory, and specific heat capacities. Learning these topics is crucial because students may get several ...

  5. Important Questions for CBSE Class 11 Physics Chapter 13 – Kinetic Theory solved by our expert teachers for academic year 2022-23. These solutions are compliant with the latest edition books, CBSE syllabus and NCERT guidelines.

  6. Question 13. 1. Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP.’. Take the diameter of an oxygen molecule to be 3 A. Answer: Diameter of an oxygen molecule, d = 3 A = 3 x 10 -10 m. Consider one mole of oxygen gas at STP, which contain total NA = 6.023 x 10 23 molecules. Question 13. 2.

  7. Chapter 13 Kinetic Theory . Answer The Following Question Answer. Question 1. Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3Å. Solution : Diameter of an oxygen molecule, d = 3Å Radius, r = d/2 = 3/2 = 1.5 Å = 1.5 × 10 –8 cm

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