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  1. 𝑔𝑔(𝑥𝑥) = −1. ℎ(5) = 3; lim 𝑥𝑥→5 ℎ(𝑥𝑥) = 5. The table above gives selected values and limits of the functions 𝑓𝑓, 𝑔𝑔, and ℎ. What is lim 𝑥𝑥→5 ℎ(𝑥𝑥) 𝑓𝑓(𝑥𝑥) + 2𝑔𝑔(𝑥𝑥) −ℎ(5) ? Example 4: Piecewise Functions . Piecewise defined functions and limits

  2. WORKSHEET: DEFINITION OF THE DERIVATIVE 1. For each function given below, calculate the derivative at a point f0(a) using the limit de nition. (a) f(x) = 2x2 3x f0(0) =? (b) f(x) = p 2x+ 1 f0(4) =? (c) f(x) = 1 x 2 f0(3) =? 2. For each function f(x) given below, nd the general derivative f0(x) as a new function by using the limit de nition. (a ...

  3. 201-103-RE - Calculus 1 WORKSHEET: LIMITS 1. Use the graph of the function f(x) to answer each question. Use 1, 1 or DNEwhere appropriate. (a) f(0) = (b) f(2) = (c) f(3) = (d) lim x!0 f(x) = (e) lim x!0 f(x) = (f) lim x!3+ f(x) = (g) lim x!3 f(x) = (h) lim x!1 f(x) = 2. Use the graph of the function f(x) to answer each question. Use 1, 1 or ...

  4. 1.5 Determining Limits Using Algebraic Properties: Next Lesson. Packet. calc_1.5_packet.pdf: File Size: 306 kb: File Type: pdf: Download File. Want to save money on printing? Support us and buy the Calculus workbook with all the packets in one nice spiral bound book. ... calc_1.5_ca2.pdf: File Size:

  5. AP Calculus AB – Worksheet 7 Introduction to Limits There are no great limits to growth because there are no limits of human intelligence, imagination, and wonder. – Ronald Reagan Answer the following questions. 1 For the function f x x2 fx5, as the x-value gets closer and closer to 3, gets closer and closer to what value? 2

  6. Graph the piecewise-defined function. Then determine the left and right limits at the indicated values. Also determine if the function is continuous at the indicated value(s).

  7. Calculus Maximus WS 1.4: Algebraic Limits Page 1 of 4 Name_____ Date_____ Period_____ Worksheet 1.4—Algebraic Limits Show all work. No Calculator 1. 32 0 42 58 lim x 316 xx → xx + = − 2. 5 21 lim 34 x 5 x → x − + = − 3. 32 2 32 21310 lim t 4416 tt t → tt t + − + = + −− 4. ( )3 0 28 lim x x → x + − = 5. ( )2 ( ) (2) 0