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For logarithmic equations, logb(x) = y log b (x) = y is equivalent to by = x b y = x such that x> 0 x> 0, b> 0 b> 0, and b ≠ 1 b ≠ 1. In this case, b = 7 b = 7, x = 343 x = 343, and y = 3 y = 3. Substitute the values of b b, x x, and y y into the equation by = x b y = x.
- Evaluate log base 7
Rewrite log7 (343) = x log 7 (343) = x in exponential form...
- Evaluate log base 7
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Rewrite log7 (343) = x log 7 (343) = x in exponential form using the definition of a logarithm. If x x and b b are positive real numbers and b b does not equal 1 1, then logb (x) = y log b (x) = y is equivalent to by = x b y = x. Create equivalent expressions in the equation that all have equal bases.
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x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) f(x)
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29 Νοε 2015 · How do you evaluate log7(343)? ⇒ x = 3. In most cases a question like this would require the use of a calculator. In this case the question was obviously set up for a direct solution.
