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  1. Simplify each of the following logarithmic expressions, giving the final answer as a single logarithm. a) log 7 log 22 2+ b) log 20 log 42 2− c) 3log 2 log 85 5+ d) 2log 8 5log 26 6− e) log 8 log 5 log 0.510 10 10+ − log 142, log 52, log 645, log 26, log 8010

  2. Solving Logarithmic Equations (Word Problems) Example 1. INVESTMENT Mr. and Mrs. Mitchell are saving for their daughter’s college education. They invest $10,000 in an account that pays 4.5% interest compounded continuously with the goal to have twice that amount in the account in ten years. a.

  3. 8. Prove the following statements. (1) logp b x = 2log x (2) log p1 b p x = log x (3) log 4 x2 = log p x 9. Given that log2 = x, log3 = y and log7 = z, express the following expressions

  4. Section 1. Logarithms. The mathematics of logarithms and exponentials occurs naturally in many branches of science. It is very important in solving problems related to growth and decay. The growth and decay may be that of a plant or a population, a crystalline structure or money in the bank.

  5. Express the equation in exponential form and solve the resulting exponential equation. Simplify the expressions in the equation by using the laws of logarithms. Represent the sums or differences of logs as single logarithms. Square all logarithmic expressions and solve the resulting quadratic equation. ____ 13.

  6. Word Problems. The applications found here will mostly involve exponential equations. These equations will be solved using logarithms and their properties. Interest Problems. Compound Interest – If we start with a principal of P dollars then the amount A in an account after t years, with an annual interest rate r compounded n times a year, is given

  7. Math 3201 Word Problems Involving Logarithms. 7.4B Word Problems Involving Logarithms. Here will we look at application problems very similar to those back in Unit 6, except this time we will have to use logarithms to solve them. Interest Problems. Recall the following from Unit 6 about compound interest problems: = (1 + ) Where :

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