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  1. The segment connecting the midpoints of two sides of a triangle is parallel to the third side and is half as long. If the three sets of corresponding sides of two triangles are in proportion, the triangles are similar. If two angles of one triangle are congruent to two angles of another triangle, the triangles are similar.

  2. An angle bisector of a triangle divides the opposite sides into two segments whose lengths are proportional to the lengths of the other two sides. If two angles and a non-included side of one triangle are equal in measure to the corresponding angles and side of another triangle, then the triangles are congruent.

  3. In this unit you will extend your knowledge of a logical procedure for verifying geometric relationships. You will analyze conjectures and verify conclusions. You will use definitions, properties, postulates, and theorems to verify steps in proofs. The proofs in this lesson will focus on segment and angle relationships.

  4. Prove statements about segments and angles. I can explain the structure of a two-column proof. I can write a two-column proof. I can identify properties of congruence. statement is true. Why does the order of the statements and reasons in a proof matter? Work with a partner. Complete the statements to prove that AB BC. = . By the , AB BC AC. = + .

  5. Name the plane represented by each P surface of the box. squares and angles, are formed by parts of lines called segments or A rays.A segment is the part of a Endpoint line consisting of two endpoints and all points between them.

  6. GEOMETRY POSTULATES AND THEOREMS Postulate 1: Through any two points, there is exactly one line. Postulate 2: The measure of any line segment is a unique positive number. The measure (or length) of AB is a positive number, AB.

  7. Special Segments in Triangles Part 1 March 22, 2015 A segment whose endpoints are a vertex of a triangle and the midpoint of the opposite side. The point of concurrency of the medians. Perpendicular Bisector Angle Bisector Altitude Circumcenter Incenter Orthocenter

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