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I've been trying to figure out how I can make a query with MySQL that checks if the value (string $haystack) in a certain column contains certain data (string $needle), like this: SELECT * FROM `table` WHERE `column`.contains('{$needle}')
12 Φεβ 2024 · One effective method to check if a particular string occurs in a MySQL table is by utilizing the SELECT statement along with the LOCATE() function. The LOCATE() function in MySQL is employed to find the position of the first occurrence of a substring within a given string. Its syntax is as follows: LOCATE(substring, string); Where:
12 Μαΐ 2024 · SELECT * FROM Product WHERE CHARINDEX('Milk', description) > 0 OR CHARINDEX('Dark', description) > 0; Like POSITION() , CHARINDEX() returns the 1-based index of the search substring or 0 if it isn’t in the string.
Pattern matching using an SQL pattern. Returns 1 (TRUE) or 0 (FALSE). If either expr or pat is NULL, the result is NULL. The pattern need not be a literal string. For example, it can be specified as a string expression or table column.
String values can be converted to a different character set using CONVERT(). See Section 14.10, “Cast Functions and Operators”. By default, string comparisons are not case-sensitive and use the current character set. The default is utf8mb4. = Equal: mysql> SELECT 1 = 0; -> 0. mysql> SELECT '0' = 0; -> 1. mysql> SELECT '0.0' = 0; -> 1.
MySQL REGEXP operator examples. We’ll take some examples of using the REGEXP operator. 1) Simple REGEXP operator examples. The following example uses the REGEXP operator to check if a string contains any digits: SELECT 'MySQL 8.0' REGEXP '\\d+'; Code language: SQL (Structured Query Language) (sql) Output: + ---------------------------+ .
MAKE_SET(bits, str1, str2,...) Returns a set value (a string containing substrings separated by , characters) consisting of the strings that have the corresponding bit in bits set. str1 corresponds to bit 0, str2 to bit 1, and so on. NULL values in str1, str2, ... are not appended to the result.
