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To find the correct oxidations state of S in H2SO4 (Sulfuric acid), and each element in the molecule, we use a few rules and some simple math.First, since th...
Enter the formula of a chemical compound to find the oxidation number of each element. A net ionic charge can be specified at the end of the compound between { and }. For example: ZnCl4{2-} or NH2NH3{+}. Enter just an element symbol to show the common and uncommon oxidation states of the element.
In sulfuric acid (H2SO4), the oxidation number of sulfur is +6. We find this by knowing that hydrogen has an oxidation number of +1 (totaling +2 for the two hydrogen atoms), and oxygen has an oxidation number of -2 (totaling -8 for the four oxygen atoms).
11 Ιαν 2014 · The oxidation number of sulfur depends on the compound it is in. For example, In H₂SO₄, the oxidation number of S is +6. In Na₂S₂O₆, the oxidation number of S is +5. In H₂SO₃, the oxidation number of S is +4.
Sulfuric acid is a strong protic acid, which in dilute solutions (in water) reacts as a dibasic acid, (9.8.9), forming bisulfate (HSO 4-) and sulfate (SO 4 2-) anions. A large number of salts are known for both anions. In addition, sulfate is known to act as a monodentate or bidentate ligand in coordination complexes.
23 Απρ 2018 · Explanation: In H 2SO4, hydrogen exists in its usual +1 state, and oxygen exists in its −2 state. Let x be the oxidation number of sulfur in sulfuric acid. Then we got: 1 ⋅ 2 + x −2 ⋅ 4 = 0. 2 + x − 8 = 0. x − 6 = 0. x = 6. So, sulfur exists in the +6 state.
Using oxidation states to determine reaction stoichiometry; Contributors; This page explains what oxidation states (oxidation numbers) are and how to calculate and use them.
