Αποτελέσματα Αναζήτησης
8 Ιουλ 2024 · Here, \( Na2SO4 \) is sodium sulfate and \( nH2O \) represents the water of hydration. Step 2: Calculate the molar mass of the components - The molar mass of \( Na2SO4 \): - Sodium (Na): \( 22.99 \, g/mol \times 2 = 45.98 \, g/mol \) - Sulfur (S): \( 32.07 \, g/mol \) - Oxygen (O): \( 16.00 \, g/mol \times 4 = 64.00 \, g/mol \) Total for ...
A hydrated salt, Na 2 SO 4. nH 2 O undergoes 56% loss in weight on heating and become anhydrous. The value of n(approximately) will be : (PLEASE ANSWER IN A EASY TO UNDERSTAND MANNER)
7 Ιουν 2024 · Last updated. 7 June 2024. Water of Crystallisation. Water of crystallisation is when some compounds can form crystals which have water as part of their structure. A compound that contains water of crystallisation is called a hydrated compound.
7 Ιουν 2024 · The water of crystallisation is separated from the main formula by a dot when writing the chemical formula of hydrated compounds. E.g. hydrated copper (II) sulfate is CuSO 4∙ 5H 2 O. A compound which doesn’t contain water of crystallisation is called an anhydrous compound. E.g. anhydrous copper (II) sulfate is CuSO 4.
The water present in the latter case is called water of hydration or water of crystallization. Common examples of minerals that exist as hydrates are gypsum (\(\ce{CaSO4*2H2O}\)), Borax (\(\ce{Na3B4O7*10H2O}\)) and Epsom salts (\(\ce{MgSO4*7H2O}\)).
1 Ιουν 2019 · The hydrated salt, `Na_(2)SO_(4)*nH_(2)O` undergoes `55.9%` loss in weight on heating and becomes anhydrous. The value of `n` will be: A. `5` B. `3` C. `7` D. `10`
By solving this we will get $ n = 10 $ . The hydrated salt was $ N{a_2}S{O_4}.10{H_2}O $ . So, option D is correct. Note Sodium sulphate is used as a thermal storage.
