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iif = @(varargin) varargin{2*find([varargin{1:2:end}], 1, 'first')}(); You use this function as. iif(condition_1,value_1,...,true,value_final) where you replace the dots with any number of additional condition/value pairs. The way this works is that it picks among the values the first one whose condition is true.
Description. if expression, statements, end evaluates an expression, and executes a group of statements when the expression is true. An expression is true when its result is nonempty and contains only nonzero elements (logical or real numeric). Otherwise, the expression is false.
20 Αυγ 2023 · For if elsif else conditionals, Matlab executes the statements in the first block who's logical expression true, then it jumps to end. Only one block of statements is executed. The else is synonymous with "otherwise".
24 Ιουν 2022 · In an if/elseif statement, a series of possible conditions are checked in order. The order is important because as soon as one condition is satisfied, the commands inside of that if (or elseif) are executed, and no other conditions are checked (i.e., all of the other elseif and an else if it exists are skipped).
29 Σεπ 2021 · if elseif else statement not working. Hello, I have just gotten back into matlab and I am practicing the else if statememts. this is currently what I am running: function [L,w,o] = SortLargestNumber (input,input1,input2) x = input; c = input1; m = input2. HighestNumber = 0; if x>c && m. HighestNumber = x;
elseif a == 30 % if else if condition is true. fprintf('Value of a is 30\n' ); else % if none of the conditions is true '. fprintf('None of the values are matching\n'); fprintf('Exact value of a is: %d\n', a ); end. When the above code is compiled and executed, it produces the following result −.
7 Φεβ 2019 · I think the correct if statement is below. How do I count the error rate: function [x1,x2,errorRate,rTime]= RightsimulateDDM (U1,U2,dT,a,To) N= 1000; %number of simulations performed. rTime= zeros (1,N);%create a row vector for the reaction time of each simulation. for trialNumber= 1:N. x1 (1)= 0.5*a;
