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GAS VOLUMES 1. Volume (dm3) = 24 x moles. vol (dm3) 24 moles. The volume must be in dm3 (there are 1000 cm3 in 1 dm3). vol in dm3 = vol in cm3 1000. Give all answers to 3 significant figures.
Determine the volume of oxygen needed to react with 150 cm 3 of propane and the total volume of the gaseous products. Answer. The balanced equation shows that 5 moles of oxygen are needed to completely react with 1 mole of propane; Therefore, the volume of oxygen needed would be = 5 moles x 150 cm 3 = 750 cm 3
Find the volume the gas will occupy at -39.9 °C if the pressure remains constant. A sample of gas has a volume of 215 cm3 at 23.5 °C and 84.6 kPa. What volume will the gas occupy at STP? At a certain temperature, molecules of methane gas, CH4 have an average velocity of 0.098 m/s.
Calculating Gas Volumes from Equations. One result of this property of gasses is that, if we have a balanced equation where one or more of the chemicals involved is a gas, we can work out the volume of space occupied by this gas at 20\degree\text {C and }1\text { atm}.
Calculate V 2. The volume that "escapes" is V 2 minus 2.05 L. Usually, a Charles' Law problem asks for what the volume is at the end (the V 2 in this question) or at the start, before some temperature change. This question asks you for the difference between V 1 and V 2.
Worksheet CHEM 150: Ch. 10 Ideal Gas Law 1. How many moles of gas (air) are in the lungs of an adult with a lung capacity of 3.9 L? Assume that the lungs are at 1.00 atm pressure and at a body temperature of 40 o C. ! ∙ $%& (Hint: V, P, and T are given. Use the equation PV = nRT where R = 0.082058 ) ’∙ &() 2.
Calculate the total volume of gases after the reaction has completed. Show your working clearly. 2.0 dm3 of PCl3 would need 2.0 dm3 of Cl2 for complete reaction, but there is only 1.5 dm3 of Cl2, so Cl2 is limiting reagent. 1.5 dm3 of PCl3 reacts (0.5 dm3 leftover) with 1.5 dm3 of Cl2 to form 1.5 dm3 of PCl5.
