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Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It uses functions such as sine, cosine, and tangent to describe the ratios of the sides of a right triangle based on its angles. The three basic trigonometric functions are: Sine (sin), Cosine (cos), and Tangent (tan).
The Pythagorean Theorem says that, in a right triangle, the square of a plus the square of b is equal to the square of c: a 2 + b 2 = c 2. Dividing through by c 2 gives. a 2 c 2 + b 2 c 2 = c 2 c 2. This can be simplified to: (ac) 2 + (bc) 2 = 1. a/c is Opposite / Hypotenuse, which is sin(θ) b/c is Adjacent / Hypotenuse, which is cos(θ) So (a ...
tan(x y) = (tan x tan y) / (1 tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos ^2 (x) - sin ^2 (x) = 2 cos ^2 (x) - 1 = 1 - 2 sin ^2 (x)
Free math problem solver answers your trigonometry homework questions with step-by-step explanations.
Posing X = x+y and Y = x−y, the determinant becomes: Δ = ∣∣∣∣∣∣∣ cos(X) sin(Y) sin(X +Y) sin(X) cos(Y) 0 −cos(X) sin(Y) sin(X −Y) ∣∣∣∣∣∣∣ ... From the comment by GWu: Your general solution involves eix and xeix. So if you want the particular solution with sinx and cosx (which are disguised forms of eix and e−ix ...
When the height and base side of the right triangle are known, we can find out the sine, cosine, tangent, secant, cosecant, and cotangent values using trigonometric formulas. The reciprocal trigonometric identities are also derived by using the trigonometric functions.
prove\:\cot(2x)=\frac{1-\tan^2(x)}{2\tan(x)} prove\:\csc(2x)=\frac{\sec(x)}{2\sin(x)} prove\:\frac{\sin(3x)+\sin(7x)}{\cos(3x)-\cos(7x)}=\cot(2x) prove\:\frac{\csc(\theta)+\cot(\theta)}{\tan(\theta)+\sin(\theta)}=\cot(\theta)\csc(\theta)
