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  1. The key takeaways are that the book is intended to teach English grammar to second language learners in a functional way to help them use English correctly and naturally. Grammatical terminology is used sparingly and exercises are designed for independent practice.

  2. Question 1 Simplify each of the following logarithmic expressions, giving the final answer as a single logarithm. a) log 7 log 22 2+ b) log 20 log 42 2− c) 3log 2 log 85 5+ d) 2log 8 5log 26 6− e) log 8 log 5 log 0.510 10 10+ − log 142, log 52, log 645, log 26, log 8010

  3. The change of base rule: log a. c. = log. c b. There are two common abbreviations for logarithms to particular bases: log. 10 x is often written as log x. loge x is often written as ln x. The graphs of exponential and logarithmic functions:

  4. explain what is meant by a logarithm. state and use the laws of logarithms. solve simple equations requiring the use of logarithms. Contents. Introduction. Why do we study logarithms ? What is a logarithm ? if x = an then loga x = n. 4. Exercises. 5. The first law of logarithms. loga xy = loga x + loga y. 6. The second law of logarithms.

  5. Study the statement. 100 = 102. In this statement we say that 10 is the base and 2 is the power or index. Logarithms provide an alternative way of writing a statement such as this. We rewrite it as. log10 100 = 2. This is read as ‘log to the base 10 of 100 is 2’. These alternative forms are shown in Figure 1. index or power. 100 = 102 log 100.

  6. www.ibmathematics.org › wp-content › uploadsIntro to logarithms

    De nition. a > 0, a 6= 1 and b > 0 we have: loga b = c , ac = b. What does it mean? First of all the assumptions (restrictions) are important. The number a, called the base of the logarithm, has to be greater than 0 and cannot be equal to 1. The number b (which we take the logarithm of) has to be greater than 0.

  7. We use can logarithms to solve exponential equations: = b is x = log a bFor example, the solution of ex. 2 is x = log e 2. To find the value of this logarithm, we need to use a calculator. log e 2 = 0.6931.Note Logarithms were invented and used for solving exponential equations by the Scottish baron John Napi.

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