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Illustrate the reaction of an insoluble metal oxide with a dilute acid to produce crystals of a soluble salt in this class practical. Includes kit list and safety instructions.
14 Απρ 2021 · You can imagine concentrated sulfuric acid as an oxidising agent which supplies [O]. The copper takes the [O] and become CuO while sulfuric acid become sulfur dioxide. Then CuO reacts with remaining sulfuric acid to form CuX2SOX4 C u X 2 S O X 4.
Copper(II) oxide or cupric oxide is an inorganic compound with the formula CuO. A black solid, it is one of the two stable oxides of copper, the other being Cu 2 O or copper(I) oxide (cuprous oxide). As a mineral, it is known as tenorite, or sometimes black copper.
As a result, hydroxide ion can displace water from the copper (II) ion, yielding copper hydroxide, Cu (OH) 2, a blue precipitate. Heating copper hydroxide produces copper oxide, CuO, a black solid. Copper oxide dissolves in acid, regenerating the copper (II) ion, which once again binds to water.
Mixing copper oxide and sulphuric acid is an experiment involving an insoluble metal oxide which is reacted with a dilute acid to form a soluble salt. Copper (II) oxide, is a black solid, which, when reacted with sulphuric acid creates a cyan-blue coloured chemical called copper II sulfate.
The overall equation for the reaction between copper(II) oxide and dilute sulfuric acid is CuO(s) + H 2 SO 4 (aq) CuSO 4 (aq) + H 2 O(l) Oxide ions from the copper(II) oxide and hydrogen ions from the acid have combined to make water and aren't there any longer.
25 Ιουν 2018 · Explanation: This is simply an acid-base reaction... And it is good to do because CuSO4(aq) forms a lovely, blue-coloured solution due to the formation of [Cu{(OH)2}6]2+...i.e.
