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Problem #1: Calculate the decrease in temperature (in Celsius) when 2.00 L at 21.0 °C is compressed to 1.00 L. Solution: (2.00 L) / 294.0 K) = (1.00 L) / (x) cross multiply to get: 2x = 293. x = 147.0 K. Converting 147.0 K to Celsius, we find -126.0 °C, for a total decrease of 147.0 °C, from 21.0 °C to -126.0 °C.
- Law Examples and Problems Only
Problems 1-10. Problem #1: Calculate the decrease in...
- Charles
Charles' Law gives the relationship between volume and...
- Problems 11-25
The much, much more common equation for Charles' Law problem...
- Law Examples and Problems Only
Charles’ law is an experimental gas law that describes how gases expand when heated. It gives a formal relationship between temperature and volume. Charles’ law states that the volume occupied by a gas at constant pressure is proportional to its temperature.
Charles's Law states that the volume of a given mass of gas varies directly with the absolute temperature of the gas when pressure is kept constant. The absolute temperature is temperature measured with the Kelvin scale.
30 Μαρ 2021 · Charles’s law or the law of volumes is an ideal gas law that states that the volume and temperature of a fixed amount of gas are proportional at constant pressure. Doubling the temperature of a gas doubles its volume.
8 Δεκ 2019 · Charles' law is a special case of the ideal gas law at constant pressure. This example shows how to use Charles' law to solve real-world gas problems.
Problems 1-10. Problem #1: Calculate the decrease in temperature when 2.00 L at 20.0 °C is compressed to 1.00 L. Problem #2: 600.0 mL of air is at 20.0 °C. What is the volume at 60.0 °C? Problem #3: A gas occupies 900.0 mL at a temperature of 27.0 °C. What is the volume at 132.0 °C?
The much, much more common equation for Charles' Law problem solving is V 1 / T 1 = V 2 / T 2. Bonus Problem: In an air-conditioned room at 19.0 #&176;C, a spherical balloon had the diameter of 50.0 cm. When taken outside on a hot summer day, the balloon expanded to 51.0 cm in diameter.
