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Find the locus of a point equidistant from two given points. Solution. Verified by Toppr. (i) Let a, b be the position vectors of the given points A, B, with reference to any origin, O. If r be the position vector of any point P on the locus, we have. P.
Click here:point_up_2:to get an answer to your question :writing_hand:find thepoint on the x axis which is equidistant from 25 and 29.
Find a relation between x and y such that the point (x,y) is equidistant from the points (7,1) and (3,5).
If P(x, y) is equidistant from the points A(7, 1) and B(3, 5), find the relation between x and y.
If the point P(x, 3) is equidistant from the point A(7, −1) and B(6, 8), then find the value of x and find the distance AP.
Find a point on the x-axis, which is equidistant from the points (5, 4) and (2, 3). View Solution. Q3.
Question 9 If Q (0, 1) is equidistant from P (5, - 3) and R (x, 6), find the values of x. Also find the distance QR and PR.
Since A (3, y) is equidistant from points P (8, − 3) and Q (7, 6), then, A P = A Q. √ (3 − 8) 2 + (y − (− 3)) 2 = √ (3 − 7) 2 + (y − 6) 2. √ (5) 2 + (y + 3) 2 = √ (4) 2 + (y − 6) 2. √ 25 + y 2 + 9 + 6 y = √ 16 + y 2 + 36 − 12 y. √ y 2 + 6 y + 34 = √ y 2 − 12 y + 52. Squaring both sides, y 2 + 6 y + 34 = y 2 − ...
Find the point on x-axis which is equidistant from points A(−1, 0) and B(5, 0). [CBSE 2013C] View ...
If (a, a) is equidistant from the points (-1, 3) and (2, -4), find the value of a. View Solution
